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Gaurav
Questions (9)
I am a 4 digit number between 2000 and 5000. Each of my digit is an even number. Also,all my digits are identical. Who am I
3 answers
1,989 views
the number of solution of |sinx| = |cos3x| in the interval (-2π,3π)
1 answer
363 views
The rails on a railroad are 30 feet long. As the train passes over the point where the rails are joined, there is an audible
3 answers
1,015 views
09+36=75
05+04=23 08+01=63 06+16=32 09+09=78 03+09=6 03+81=?? Can u solve & share the logic behind this??
1 answer
770 views
display table of 2,in the form of 2*1=2
0 answers
312 views
I am making a object oriented program and hashing the list of make of an electronic and type to the JCombobox...i am getting
4 answers
455 views
Find the angular velocity of a body rotating with an acceleration of 2 rev/s square as it completes the 5th revolution after the
1 answer
512 views
After writing the program of Exercise 17.7, write a simple program to create some test data for checking out the program. Use
1 answer
620 views
Calculate the root mean square,average and most probable speed of oxygen at 27degree celcius
2 answers
594 views
Answers (9)
A=3x B=4x C=5x Perimeter=a+b+c=24cm =3x+4x+5x=24cm =12x=24cm =x=24/12=2cm =x=2cm. =A=3x=3×2=6 =B=4x=4×2=8 =C=5x=5×2=10 S(semi perimeter) = a+b+c/2 S(semi perimeter) =6+8+10/2 =24/2=12. ∆=√S(s-a)(s-b)(s-c) =√12(12-6)(12-8)(12-10) =√12×6×4×2
Multiple of 27 = 9 x 3 Multiple of 14 = 7 x 2 Therefore, the should be 79 x 23 Or 29 x 73 Whose product will be 2117 ? Is 29 x 73 yes Therefore it is your answer
A cyclist travel a distance of 4km from P to q and then moves a distance of 3km at the right angle to PQ. Find his resultant displacement graphically.
Please do not answer these questions, It is not a help. It is challenge for a new education system, I think this should be immediately stopped to cheer at least those who are working hard to learn
the question is not complete.. linear functions do not have asymptote...
V1 =19.5gellon=2113.2cm^3 TM1 =2113.2*1.0837= 22900.9 g M1= 12*TM1= 2748.1 g V2 =? TM2 =V2*1.1453 M2 = 20*V2*1.1453 V3=V1+V2 (mixing of two solutions) Conservation of mass: M3=M1+M2, M3= 12*V1*1.0837 + 20*V2*1.1453 ....I TM3 = TM1+TM2, M3 = 19*TM3 =
New Value of account= $5000*(1+12/100)^5 = $8811.7
thanks...yes i found the error. It was basically trying to parse a null which is a string. Yes i can try and catch the exception but haven't learned it but thanks for idea...i think i mite do that.
(10x-21)/(x^2-9)
