Asked by wan

2poles are placed vertically in a pool.one third of the longer pole and two fifths of the shorter pole is under water.if the difference in leng 42 cm,how deep is the pool?th
Answered by bobpursley
L-S=42
now water height is the same, so
1/3 L = 2/5 S

L-S=42
5L-6S=0

solve.
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