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2poles are placed vertically in a pool.one third of the longer pole and two fifths of the shorter pole is under water.if the difference in leng 42 cm,how deep is the pool?th
12 years ago

Answers

bobpursley
L-S=42
now water height is the same, so
1/3 L = 2/5 S

L-S=42
5L-6S=0

solve.
12 years ago

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