Question

Which function would vertically stretch c(x)=√2x-1+3
by a factor of 5?(1 point)
Responses

m(x)=√2/5x-1+3
m left parenthesis x right parenthesis equals Start Root Start Fraction 2 over 5 End Fraction x minus 1 End Root plus 3

d(x)=√10x-1+3
d left parenthesis x right parenthesis equals Start Root 10 x minus 1 End Root plus 3

k(x)=5√2x-1+3
k left parenthesis x right parenthesis equals 5 Start Root 2 x minus 1 End Root plus 3

b(x)=1/5√2x-1+3

Answer 1

To vertically stretch a function by a factor of 5, you multiply the entire function by 5.

The original function is \( c(x) = \sqrt{2x - 1} + 3 \).

To vertically stretch this function by a factor of 5, you would multiply the square root term by 5:

\[
k(x) = 5(\sqrt{2x - 1}) + 3
\]

Thus, the correct function after the vertical stretch is:

\[
k(x) = 5\sqrt{2x - 1} + 3
\]

So the correct choice from the given responses is:

**k(x) = 5√(2x - 1) + 3**.