Asked by ladybug
Write the equation of the circle in standard form. Find the center, radius and intercepts.
x^2 + y^2 + 4x + 2y - 20 = 0
x^2 + y^2 + 4x + 2y - 20 = 0
Answers
Answered by
Reiny
complete the square
x^2 + 4x <b>+ 4 </b> + y^2 + 2y <b>+ 1 </b> = 20 <b>+ 4 </b> <b>+ 1 </b>
(x+2)^2 + (y+1)^2 = 25
I will let you handle the rest, since this is a very basic result.
x^2 + 4x <b>+ 4 </b> + y^2 + 2y <b>+ 1 </b> = 20 <b>+ 4 </b> <b>+ 1 </b>
(x+2)^2 + (y+1)^2 = 25
I will let you handle the rest, since this is a very basic result.