Asked by Shawn
                Write the equation of the circle centered at (6,10) that passes through (-9,1)
            
            
        Answers
                    Answered by
            Reiny
            
    centre at (6,10), so the equation is
(x-6)^2 + (y-10)^2 = r^2
sub in your point (-9,1) to solve for r^2
then rewrite my equation. All done!
    
(x-6)^2 + (y-10)^2 = r^2
sub in your point (-9,1) to solve for r^2
then rewrite my equation. All done!
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