Asked by Shawn
Write the equation of the circle centered at (6,10) that passes through (-9,1)
Answers
Answered by
Reiny
centre at (6,10), so the equation is
(x-6)^2 + (y-10)^2 = r^2
sub in your point (-9,1) to solve for r^2
then rewrite my equation. All done!
(x-6)^2 + (y-10)^2 = r^2
sub in your point (-9,1) to solve for r^2
then rewrite my equation. All done!
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