Asked by Kathryn
write the equation of the circle passes through the point (√5,0) and whose center is the origin
Answers
Answered by
MathMate
Circle centred at origin:
x²+y²=r²
where r=radius.
Here radius = √((√5)²+0²)=√5
x²+y²=r²
where r=radius.
Here radius = √((√5)²+0²)=√5
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