Asked by Anonymous
A toy race car starts from rest on a circular track of radius 4.30 m. The cars speed increases at the constant rate of 8.80 m/s2. At the point where the magnitudes of the centripetal and tangential accelerations are equal, determine (a) the speed of the race car. b) the elapsed time c)the distance traveled
Answers
Answered by
Elena
R=4.3 m, a(τ)=8.8 m/s².
a(τ)=a(c) =v²/R =>
v=sqrt{a(c) •R}= sqrt{a(τ) •R}=
=sqrt{8.8•4.3}=6.15 m/s.
v=a(τ) •t,
t= v/a(τ)=6.15/8.8 =0.699 s= 0.7 s.
s= a(τ) •t²/2 =8.8•0.7²/2=2.156 m.
a(τ)=a(c) =v²/R =>
v=sqrt{a(c) •R}= sqrt{a(τ) •R}=
=sqrt{8.8•4.3}=6.15 m/s.
v=a(τ) •t,
t= v/a(τ)=6.15/8.8 =0.699 s= 0.7 s.
s= a(τ) •t²/2 =8.8•0.7²/2=2.156 m.