Question
A race car driver starts along a 50-mile race course traveling at an average speed of 90 mph. Fifteen minutes later a second driver starts along the same course at an average speed of 120 mph. Will the second car overtake the first car before the drivers reach the end of the course?
Answers
Mithra
First race car driver:
time = distance / speed
time = 50 miles / 90 mph
time = 0.55556 x 60
time = 33 minutes 20 seconds
The first race car driver will took 33 minutes & 20 seconds to finish the race
Fifteen minutes later a second race car drive start
time = distance / speed
time = 50 miles / 120 mph
time = 0.41667 x 60
time = 25 minutes
The second race car driver will took 25 minutes to complete the 50 miles
Now, add 25 minutes & 15 minutes = 40 minutes
Therfore, the first race car driver will finish 6 minutes & 40 seconds before the second race car driver.
time = distance / speed
time = 50 miles / 90 mph
time = 0.55556 x 60
time = 33 minutes 20 seconds
The first race car driver will took 33 minutes & 20 seconds to finish the race
Fifteen minutes later a second race car drive start
time = distance / speed
time = 50 miles / 120 mph
time = 0.41667 x 60
time = 25 minutes
The second race car driver will took 25 minutes to complete the 50 miles
Now, add 25 minutes & 15 minutes = 40 minutes
Therfore, the first race car driver will finish 6 minutes & 40 seconds before the second race car driver.