Asked by YOYO

A race car starts from rest on a circular track of radius 400 m. Its speed increases at the constant rate of 0.500 m/s2. At the point where the magnitudes of the radial acceleration is twice the tangential acceleration, determine (a) the speed of the race car, and (b) the elapsed time.

Answers

Answered by hey i um
hey wants the answer?
Answered by Anonymous
tangential a = 0.5 m/s^2
so
v = 0.5 t

radial a = v^2/R = 0.25 t^2/ 400 = 0.000625 t^2
at radial acc = 1.0 m/s^2 which is twice a
1.0 = 0.000625 t^2
t^2 = 1600
t = 40 seconds
v = 0.5 t = 20 m/s
Answered by Anonymous
big hurry?
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