what's the problem? Inflection points occur where f'' = 0
f' = 32x^3 + 138x^2 - 36x
f'' = 96x^2 + 276x - 36
= 8(12x^2 + 23x - 3)
f''=0 where x = -3, 1/8
Find the inflection points of f(x)=8x^4+46x^3-18x^2+1. (Give your answers as a comma separated list, e.g., 3,-2.)
Please Help!!!!!
2 answers
Find the points of inflection of the graph of the function. (If an answer does not exist, enter DNE.)
f(x) = sin
x
4
, [0, 8π]
f(x) = sin
x
4
, [0, 8π]