Asked by Angelina
Find the points of inflection of the graph of the function. (If an answer does not exist, enter DNE.)
f(x) = 1/3x^4 + 4x^3
for some reason I am not getting the right answer; I got the graph on my calculator but it seems weird.
f(x) = 1/3x^4 + 4x^3
for some reason I am not getting the right answer; I got the graph on my calculator but it seems weird.
Answers
Answered by
Susan
4/3x^3 + 12x^2 = f'(x)
4/3x^3 + 12x^2 =0
multiply by 3 to clear fractions
4x^3 + 36x^2 =0
factor out 4x^2
(4x^2)(x+9)=0
x = 0, x =-9 are critical numbers
f'(-10)= -,f'(-8) = +, f'(1) = +
(-9,-729) is an inflection, actually a minimum point
4/3x^3 + 12x^2 =0
multiply by 3 to clear fractions
4x^3 + 36x^2 =0
factor out 4x^2
(4x^2)(x+9)=0
x = 0, x =-9 are critical numbers
f'(-10)= -,f'(-8) = +, f'(1) = +
(-9,-729) is an inflection, actually a minimum point
Answered by
Angelina
Thanks for the help but I am still confused because it's asking for
smaller x-value
larger x-value
so what would that be?
smaller x-value
larger x-value
so what would that be?
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.