Question

A 4-digit number. The sum of its digits is 18. The last two digits are 5 times as much as the first 2 digits. The hundreds and ones places have the same digit.

Answer 1

The last two digits must be a multiple of 5 of a two digit number; The first two digit number is 10. So the last two digits can be

50, 55, 60, 65, . . .
If the last two digits are 50 then the number is

1050
1155
1260
1365
1470
1575--this is the first number where the hundreds and ones place have the same digit, and the sum of the digits is 18