Asked by Annonomus

 In a two-digit number the tens digit is two less than the units digit. If the digits are reversed, the sum of the reversed number and the original number is 154. Find the original number.
Answered by Damon
(n-2) n is (n-2)10 + n = 11 n-20

n (n-2) is 10 n + n-2 = 11 n - 2

sum = 22 n - 22 = 154
so
22 n = 176
n = 8
so
68

Answered by charli'damielo
compute the sum of all ten 2-digit numbers with a tens digit of 6
Answered by charli'damielo
5x5
Answered by SIDTHEKID
73
TRUST ME I GOT IT CORRECT
Answered by LOLLY POP!
68
Answered by Julie Mangan
(n-2) n is (n-2)10 + n = 11 n-20

n (n-2) is 10 n + n-2 = 11 n - 2

The sum = 22 n - 22 = 154, so we can understand that:
22 n = 176
After solving the equation;
n = 8
So, the answer is 68.
I hope this helped!
Answered by Jamie
68 trust me
There are no AI answers yet. The ability to request AI answers is coming soon!