Question
In a two-digit number the tens digit is two less than the units digit. If the digits are reversed, the sum of the reversed number and the original number is 154. Find the original number.
Answers
Damon
(n-2) n is (n-2)10 + n = 11 n-20
n (n-2) is 10 n + n-2 = 11 n - 2
sum = 22 n - 22 = 154
so
22 n = 176
n = 8
so
68
n (n-2) is 10 n + n-2 = 11 n - 2
sum = 22 n - 22 = 154
so
22 n = 176
n = 8
so
68
charli'damielo
compute the sum of all ten 2-digit numbers with a tens digit of 6
charli'damielo
5x5
SIDTHEKID
73
TRUST ME I GOT IT CORRECT
TRUST ME I GOT IT CORRECT
LOLLY POP!
68
Julie Mangan
(n-2) n is (n-2)10 + n = 11 n-20
n (n-2) is 10 n + n-2 = 11 n - 2
The sum = 22 n - 22 = 154, so we can understand that:
22 n = 176
After solving the equation;
n = 8
So, the answer is 68.
I hope this helped!
n (n-2) is 10 n + n-2 = 11 n - 2
The sum = 22 n - 22 = 154, so we can understand that:
22 n = 176
After solving the equation;
n = 8
So, the answer is 68.
I hope this helped!
Jamie
68 trust me