In a two-digit number the tens digit is two less than the units digit. If the digits are reversed, the sum of the reversed number and the original number is 154. Find the original number.

Answer 1

(n-2) n is (n-2)10 + n = 11 n-20

n (n-2) is 10 n + n-2 = 11 n - 2

sum = 22 n - 22 = 154
so
22 n = 176
n = 8
so
68

Answer 2

compute the sum of all ten 2-digit numbers with a tens digit of 6

Answer 3

5x5

Answer 4

73
TRUST ME I GOT IT CORRECT

Answer 5

68

Answer 6

(n-2) n is (n-2)10 + n = 11 n-20

n (n-2) is 10 n + n-2 = 11 n - 2

The sum = 22 n - 22 = 154, so we can understand that:
22 n = 176
After solving the equation;
n = 8
So, the answer is 68.
I hope this helped!

Answer 7

68 trust me