Asked by Anonymous
A pebble is dropped into a pond, causing ripples in the form of concentric circles. The radius r of the outer ripple is increasing at a constant rate of 2 feet per second. When the radius is 10 feet, at what rate is the total area A of the disturbed water changing?
Answers
Answered by
Steve
a = pi r^2
da/dt = 2pi r dr/dt
when r = 10,
da/dt = 2pi * 10 ft * 2 ft/s = 40pi ft^2/s
da/dt = 2pi r dr/dt
when r = 10,
da/dt = 2pi * 10 ft * 2 ft/s = 40pi ft^2/s
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