Asked by Melissa
A boy fires a 60 g pebble with his slingshot. The pebble leaves the slingshot at 35m/s
How high above the slingshot will the pebble rise if it's fired straight up?
How high above the slingshot will the pebble rise if it's fired straight up?
Answers
Answered by
Elena
KE =PE
m•v²/2 =m•g•h
h = v²/2•g =(35)²/2•9.8 =62.5 m
m•v²/2 =m•g•h
h = v²/2•g =(35)²/2•9.8 =62.5 m
Answered by
Unnamed dude who has no life
V2 2 = V1 2 + 2aΔd
0 = 35 2 + 2(-9.8)d
0 = 1225 – 19.6d
-1225 = -19.6d
62.5 = d
The pebble will reach a maximum height of 62.5m [up].
0 = 35 2 + 2(-9.8)d
0 = 1225 – 19.6d
-1225 = -19.6d
62.5 = d
The pebble will reach a maximum height of 62.5m [up].
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