Question

A pebble is dropped from an open window 100 meters above the ground.


a) What is the velocity of the pebble after 2 seconds?

b) What is the velocity of the pebble when it hits the ground?

Answer 1

v = -gt = -9.8*2

100 = 4.9 t^2
t = 4.52 seconds to ground
so
v = -9.8*4.52