Asked by Anna
A 100 kg sample of a metal is cooled from 100°C to 20°C by removing 20 kcal of heat. Calculate the specific heat capacity of the metal.
Answers
Answered by
bobpursley
20kcal=100kg*c*80 C
c=20k/(100k*8O)=.2/80=.02/8
= .0025 cal/g-C
c=20k/(100k*8O)=.2/80=.02/8
= .0025 cal/g-C
Answered by
Elena
20 kcal =83736 J
Q=cmΔT
c=Q/mΔT
Q=cmΔT
c=Q/mΔT