Question

A 150.0-g sample of metal at 80.0∘C is added to 150.0 g of H2O at 20.0∘C. The temperature raises to 23.3∘C.
Assuming that the calorimeter is a perfect insulator, what is the specific heat of the metal? [Special heat of H2O is 4.128 J/(g·∘C).]
some help would be appreciated!

Answer 1

I assume you meant "the temperature rises to ...."
(mass metal x specific heat metal x delta T) + (mass water x specific heat water x delta T) = 0
The only unknown is specific heat metal.