A 150 g sample of metal at 55.0 C raises the temperature of 150 g of water from 23.0 C to 35.0 C. Determine the specific heat of the metal in J/g C.
Hint: #1 First find heat absorbed by water using formula q = mass x specific heat x change in temp (of water).
#2 Use this value to solve for specific heat of the metal. Remember final temperatures is the same for both metal and water.
Specific heat of water is 4.184 J/g C
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heat lost by the metal + heat gained by the water = 0.
mass metal x specific heat metal x [(Tfinal-Tinital)] + [mass water x specific heat water x (Tfinal-Tinital)] = 0
mass metal x specific heat metal x [(Tfinal-Tinital)] + [mass water x specific heat water x (Tfinal-Tinital)] = 0
1 answer