Write a net ionic equation for the reaction that occurs when aqueous solutions of potassium hydroxide and nitrous acid are combined.

KOH + HNO2 ==> KNO2 + H2O

net ionic is
OH^- + H^+ ==>H2O

HNO2 (aq) + OH- (aq) ==> NO2- (aq) + H2O (l)

Sure, here's a net ionic equation for you:

2 OH- (aq) + HNO2 (aq) -> 2 H2O (l) + NO2- (aq)

To write the net ionic equation for the reaction between potassium hydroxide (KOH) and nitrous acid (HNO2), we need to first write the balanced molecular equation.

Step 1: Write the balanced molecular equation by combining the two reactants and predicting the products of the reaction:
KOH(aq) + HNO2(aq) → KNO2(aq) + H2O(l)

In this reaction, potassium hydroxide (KOH) reacts with nitrous acid (HNO2) to form potassium nitrite (KNO2) and water (H2O).

Step 2: Next, write the complete ionic equation by breaking down all the aqueous substances into their individual ions:

K+(aq) + OH-(aq) + H+(aq) + NO2-(aq) → K+(aq) + NO2-(aq) + H2O(l)

In the complete ionic equation, potassium hydroxide and nitrous acid are dissociated into their respective ions.

Step 3: Finally, write the net ionic equation by removing the spectator ions, which are the ions that appear on both sides of the equation and do not participate in the reaction:

OH-(aq) + H+(aq) → H2O(l)

In the net ionic equation, the potassium ion (K+) and nitrite ion (NO2-) are spectator ions and are not involved in the chemical reaction. Thus, we are left with the net ionic equation as shown above, which represents the actual reaction taking place.