KOH + HNO2 ==> KNO2 + H2O
net ionic is
OH^- + H^+ ==>H2O
net ionic is
OH^- + H^+ ==>H2O
2 OH- (aq) + HNO2 (aq) -> 2 H2O (l) + NO2- (aq)
Step 1: Write the balanced molecular equation by combining the two reactants and predicting the products of the reaction:
KOH(aq) + HNO2(aq) → KNO2(aq) + H2O(l)
In this reaction, potassium hydroxide (KOH) reacts with nitrous acid (HNO2) to form potassium nitrite (KNO2) and water (H2O).
Step 2: Next, write the complete ionic equation by breaking down all the aqueous substances into their individual ions:
K+(aq) + OH-(aq) + H+(aq) + NO2-(aq) → K+(aq) + NO2-(aq) + H2O(l)
In the complete ionic equation, potassium hydroxide and nitrous acid are dissociated into their respective ions.
Step 3: Finally, write the net ionic equation by removing the spectator ions, which are the ions that appear on both sides of the equation and do not participate in the reaction:
OH-(aq) + H+(aq) → H2O(l)
In the net ionic equation, the potassium ion (K+) and nitrite ion (NO2-) are spectator ions and are not involved in the chemical reaction. Thus, we are left with the net ionic equation as shown above, which represents the actual reaction taking place.