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To write the net ionic equation for the reaction between potassium hydroxide (KOH) and oxalic acid (H2C2O4), we first need to write the balanced equation for the reaction.
Step 1: Write the balanced molecular equation:
KOH (aq) + H2C2O4 (aq) → K2C2O4 (aq) + H2O (l)
Step 2: Split all the soluble ionic compounds into their respective ions:
K+ (aq) + OH- (aq) + H+ (aq) + C2O4 2- (aq) → K+ (aq) + C2O4 2- (aq) + H2O (l)
Step 3: Cancel out the common ions on both sides of the equation to get the net ionic equation:
OH- (aq) + H+ (aq) → H2O (l)
Therefore, the net ionic equation for the reaction between potassium hydroxide and oxalic acid is:
OH- (aq) + H+ (aq) → H2O (l)