well, I'd say it's 2.7 cos 11°
When you're not given much info, the formulas involved must be relatively simple. Naturally, if the ramp were horizontal (0°), all the acceleration would be horizontal.
A skier squats low and races down an 11◦ ski slope. During a 3 s interval, the skier accelerates at 2.7 m/s^2 . What is the horizontal component of the skier’s acceleration (perpendicular to the direction of free fall)? Answer in units of m/s^2.
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