A skier squats low and races down a 13 ◦ ski slope. During a 7 s interval, the skier accelerates at 4.2 m/s 2 .What is the vertical component of the skier’s acceleration? Answer in units of m/s 2

Answer 1

The vertical component of a is a*sin(16) = 3.6m/s^2*sin(16) = 0.9923m/s^2
The horizontal component = a*cos(16) = 3.6m/s^2*cos(16) = 3.4605m/s^2