Asked by Megan

A sled loaded with bricks has a total mass of 18.0 kg and is pulled at constant speed by a rope inclined at 40.0o above the horizontal. The sledge moves a distance of 16.0 m on a horizontal surface. The coefficient of kinetic friction between the sledge and surface is 0.510 .
(a) What is the tension in the rope?
b) how much work is done by the rope on the sled?
(c) What is the magnitude of the force of friction?
(d) What is the mechanical energy lost due to friction?
Answered by bobpursley
The rope is doing two things: lifting up, reducing the normal weight (and friction), and pulling the sled horizontally.

consider horizontal:

tension*CosTheta*distance=work=friction*distance
tension*CosTheta=friction=mu*(mg-tension*sinTheta)
solve for tension.

work=tension*cosTheta*distance


Answered by Megan
Can you give me the values you got so I can compare my answers to make sure I did this right?
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