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Original Question
A small fish is dropped by a pelican that is rising steadily at 0.52 m/s(b) How far below the pelican is the fish after 2.4 s?Asked by Leslie
A small fish is dropped by a pelican that is rising steadily at 0.69 m/s. How far below the pelican is the fish after 2.4 s?
Answers
Answered by
bobpursley
hf=hi+vi*t-1/2 g t^2
hf-hi= .69*2.4-4.8 (2.4)^2
distance below pelican=hi-hf
hf-hi= .69*2.4-4.8 (2.4)^2
distance below pelican=hi-hf