Asked by anonymous

A small fish is dropped by a pelican that is rising steadily at 0.61 m/s.The acceleration of gravity is 9.81 m/s2.

How far below the pelican is the fish after the
3.1 s?

Answers

Answered by Steve
Just use your good old equation of motion

s = Vot + 1/2 at^2

s = .61t - 4.9t^2
Answered by Steve
Of course, that's how far the fish drops. You have to add the height the bird has gained in the 3.1s.
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