Question
Calculate the freezing point of a solution contaning 5.0 grams of KCl and 550.0 grams of water.
answer is -0.45 C but i don't know how to get here
answer is -0.45 C but i don't know how to get here
Answers
bobpursley
KCl breaks into two particles, two ions.
deltaTf=kf*2*molesKCl/.55 kg solvent
moles KCl=5/74.5
deltaTf== -1.86*2*5/74.5*1/.55 = -.45C
deltaTf=kf*2*molesKCl/.55 kg solvent
moles KCl=5/74.5
deltaTf== -1.86*2*5/74.5*1/.55 = -.45C