Asked by Sara
calculate the freezing point of an aqueous solution of 15.5 grams of glucose dissolved in 150 grams of water
Answers
Answered by
DrBob222
mols glucose = grams/molar mass = ?
Then m = mols glucose/kg solvent
Then delta T = Kf*m
New freezing point = zero C - delta T.
Then m = mols glucose/kg solvent
Then delta T = Kf*m
New freezing point = zero C - delta T.
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