Asked by Joshua help please

Calculate the freezing point of a solution containing 12.2grams of benzoic acid, C6H5CO2H, dissolved in 250 grams of nitrobenzene, C6H5NO2. The freezing point of nitrobenzene is 7.7 C, and its freezing point depression constant is 7.0 C/m.
Answered by DrBob222
delta T = Kf*molality
Remember molality = #mols/kg solvent.
After you find delta T, then subtract that from 7.7 to find the freezing point of the solution.
Answered by Joshua
where you got the 7.7 from? and how you calculate the molality for it. I am stuck please help
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