Calculate the freezing point of a solution containing 12.2grams of benzoic acid, C6H5CO2H, dissolved in 250 grams of nitrobenzene, C6H5NO2. The freezing point of nitrobenzene is 7.7 C, and its freezing point depression constant is 7.0 C/m.

Answer 1

delta T = Kf*molality
Remember molality = #mols/kg solvent.
After you find delta T, then subtract that from 7.7 to find the freezing point of the solution.

Answer 2

where you got the 7.7 from? and how you calculate the molality for it. I am stuck please help