Asked by Jackie
A rectangular wimming pool is 40 ft wide and 45 ft long. It is surrounded on all four sides by a wooden deck of fixed width. The total area enclosed within the perimeter of the deck is 2354 sq ft. What is the width of the deck?
Answers
Answered by
bobpursley
So the area of the deck is
Area=(40+2w)w +45(2w)
solve for w.
Area=(40+2w)w +45(2w)
solve for w.
Answered by
Reiny
area of pool and deck
= (40+2x)(45+2x)
= 2354
1800 + 170x + 4x^2 = 2354
2x^2 + 85x - 277 = 0
by formula
x = 3.04 or a negative
the deck is 3.04 ft wide
check: length = 45+2(3.04) = 51.08
width = 40 + 2(3.04) = 46.08
area = 51.08 x 46.08 = appr 2353.8
= (40+2x)(45+2x)
= 2354
1800 + 170x + 4x^2 = 2354
2x^2 + 85x - 277 = 0
by formula
x = 3.04 or a negative
the deck is 3.04 ft wide
check: length = 45+2(3.04) = 51.08
width = 40 + 2(3.04) = 46.08
area = 51.08 x 46.08 = appr 2353.8
Answered by
Steve
hmmm. unfortunately, we only have the total area of pool+deck is 2354.
deck area = total area - pool area
deck area = 2354 - 40*45 = 554
now you can solve bob's equation for the deck width, with the small correction that there are two short sides:
Area=(40+2w)(2w) +45(2w)
deck area = total area - pool area
deck area = 2354 - 40*45 = 554
now you can solve bob's equation for the deck width, with the small correction that there are two short sides:
Area=(40+2w)(2w) +45(2w)
Answered by
Anonymous
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