Asked by Abdulwahan
A rectangular pool is 40 meters long and 30 feet wide. A walkway 3 feet wide surrounds the pool. What is area of the walkaway.
Answers
Answered by
PsyDAG
The length of the walkway = 46 and the width of the walkway = 36.
(46*36) - (40*30) = ?
(46*36) - (40*30) = ?
Answered by
Henry
All dimensions are assumed to be in feet.
Lo = 3 + 40 + 3 = 46 Ft. = Length of outer rectangle.
Wo = 3 + 30 + 3 36 Ft. = Width of o = uter rectangle.
Ao = Lo * Wo = 46 * 36 = 1656 Ft^2.
Ap = 40 * 30 = 1200 Ft^2.
Ao - Ap = 1656 - 1200 = 456 Ft^2. = Area of walkway.
Lo = 3 + 40 + 3 = 46 Ft. = Length of outer rectangle.
Wo = 3 + 30 + 3 36 Ft. = Width of o = uter rectangle.
Ao = Lo * Wo = 46 * 36 = 1656 Ft^2.
Ap = 40 * 30 = 1200 Ft^2.
Ao - Ap = 1656 - 1200 = 456 Ft^2. = Area of walkway.
Answered by
Henry
Another Method:
L = 2*(3+40+3) + 30 + 30 = 152 Ft. = Length of walkway.
A = L*W = 152 * 3 = 456 Ft^2.
L = 2*(3+40+3) + 30 + 30 = 152 Ft. = Length of walkway.
A = L*W = 152 * 3 = 456 Ft^2.
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