Asked by Kydanty
A pool measuring 20 meters by 22 meters is surrounded by a path of uniform width, as shown in the figure. If the area of the pool and the path combine is 1088 square meters, what is the width of the path?
Answers
Answered by
oobleck
If the path has width w, then since the path is along both sides and both ends, the total area is
(20+2w)(22+2w) = 1088
Now just solve for w.
or, just ask, which two factors of 1088 differ by 2? Since they are so close together, they will both be close to √1088 ≈ 33. So, I'd try 32 and 34.
(20+2w)(22+2w) = 1088
Now just solve for w.
or, just ask, which two factors of 1088 differ by 2? Since they are so close together, they will both be close to √1088 ≈ 33. So, I'd try 32 and 34.
Answered by
R_scott
(20 + 2 w)(22 + 2 w) = 1088 ... (10 + w)(11 + w) = 272
w^2 + 21 w - 162 = 0
factor to find w
w^2 + 21 w - 162 = 0
factor to find w
Answered by
Reiny
width of path ---- x metres
area of outer rectangle = (22+2x)(20+2x)
(22+2x)(20+2x) = 1088
expand, simplify and solve the resulting equation.
You will get two integer answers, make sure to reject the negative root.
area of outer rectangle = (22+2x)(20+2x)
(22+2x)(20+2x) = 1088
expand, simplify and solve the resulting equation.
You will get two integer answers, make sure to reject the negative root.
Answered by
bim bog
width of path ---- x metres
area of outer rectangle = (22+2x)(20+2x)
(22+2x)(20+2x) = 1088
area of outer rectangle = (22+2x)(20+2x)
(22+2x)(20+2x) = 1088
Answered by
marley
the width of the path is 3
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