Asked by Ethan
A rectangular pool measures 12 feet by 20 feet. A patio of uniform width is built around the pool. The area of both the pool and the patio together is 560 square feet. Find the width of the patio.
Answers
Answered by
mathhelper
dimensions of pool including the patio is (12+2x) by (20 + 2x), where x is the width of the patio around the pool
(12+2x)(20+2x) + 12(20) = 560
240 + 24x + 40x + 4x^2 + 240 - 560 = 0
4x^2 + 64x - 80 = 0
x^2 + 16x - 20 = 0
solve using the quadratic formula since it doesn't factor.
(12+2x)(20+2x) + 12(20) = 560
240 + 24x + 40x + 4x^2 + 240 - 560 = 0
4x^2 + 64x - 80 = 0
x^2 + 16x - 20 = 0
solve using the quadratic formula since it doesn't factor.
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