Asked by James
particle A moves along the line y = 30m with a constant velocity of magnitude 3.5 m/s and parallel to the x axis. At the instant particle A passes the y axis, particle B leaves the origin with 0 initial speed and constant acceleration of magnitude 0.50 m/s2. What angle θ between and the positive direction of the y axis would result in a collision
i have tired everything i know you have to use the cosine and sin law but stil cant work it out
i have tired everything i know you have to use the cosine and sin law but stil cant work it out
Answers
Answered by
bobpursley
tried everything?
They have the same final (x,y) position
xfa=xfb
3.5t=1/2*.5*t^2,
tf= 14 sec
They have the same final y
yfa=30=yfb
But particle B started at the origin.
Theta between y axis and line
TanTheta=xchange/ychange=(3.5*14)/30
solve for Theta.
They have the same final (x,y) position
xfa=xfb
3.5t=1/2*.5*t^2,
tf= 14 sec
They have the same final y
yfa=30=yfb
But particle B started at the origin.
Theta between y axis and line
TanTheta=xchange/ychange=(3.5*14)/30
solve for Theta.
Answered by
Anne
56
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