A particle moves on a line away from its initial position so that after t hours it is s = 6t^2 + 2t miles from its initial position. Find the average velocity of the particle over the interval [1, 4]. Include units in your answer.

Answer 1

after 1 sec, d = 6(1) + 2 = 8
after 4 sec, d = 6(16) + 2(4) = 104

avg velocity = total distance/total time
= (104-8)(4-1) = 32 miles/hr