Asked by Alexis
A hydraulic lift office chair has its seat attached to a piston with an area of
11.2 cm2
. The chair is raised by exerting force on another piston, with an area
of 4.12 cm2
. If a person sitting on the chair exerts a downward force of 219 N,
what force needs to be exerted on the small piston to lift the seat?
11.2 cm2
. The chair is raised by exerting force on another piston, with an area
of 4.12 cm2
. If a person sitting on the chair exerts a downward force of 219 N,
what force needs to be exerted on the small piston to lift the seat?
Answers
Answered by
Damon
Force on big piston/force on small piston = 11.2/4.12 = 2.72 which is the mechanical advantage of our hydraulic jack machine
219/2.72 = 80.5 Newtons
That is a pretty light person by the way.
219/2.72 = 80.5 Newtons
That is a pretty light person by the way.
Answered by
Mattie
80.56 N
Answered by
shae
11.2/4.12=2.72, 219/2.72=80.5 N
thanks Ms. Smith!
thanks Ms. Smith!
Answered by
Sofía
A1 = 4.12 x 219 / 11.2 = 80.5N
Answered by
FEEFEE
So to get the answer you have to subtract the numbeer by itself then add that number you subtracted it to the answer that you got then add 2 the 3 then subtract 5 then you multiply the divide then you got your answer and ready to go. You are welcome I am the smartest person in the world
Answered by
Smile
This isn't an answer but WHO TF IS THUMBS DOWNING THESE AWESOME ANSWERS??? (to the guy downvoting: i bet u still used their answers u monster)