Asked by Anonymous

what average force is needed to accelerate a 7.00-gram pellet from rest to 125m/s over distance of a .800m along the barrel of a rifle.
Answered by Henry
a = (V^2-Vo^2)/2d.
a = (15625-0)/1.60 = 9766 m/s^2.

F = ma = 0.007 * 9766 = 68.4 N.
Answered by Anonymous
what steps did you take to get the numbers for (a)
Answered by Anonymous
V^2= U^2 + 2as
125^2 = 2a(0.8)
15625 = 1.6a
a = 9765.62 m/s^2

F = ma
= (0.007)(9765.62)
= 68.4 N
Answered by gkejafdgjafdl;'h
WHAT THE HELLA RE YOU GUYS DOING
Answered by mads
why are u getting 0.007
Answered by mads
nevermind you have to take g to kg in order to get N right
Answered by laur
yeah mads
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