Asked by Marina
How much force is needed to accelerate a 125 kg block up a 35 degree include at 3.4 m/s2 if the coefficient of friction is 0.28?
Answers
Answered by
bobpursley
net force up= F-gravitydown-friction
= F-mgsinTheta-mg*mu*cosTheta
so
F-mgsinTheta-mg*mu*cosTheta= m*a
solve for F
= F-mgsinTheta-mg*mu*cosTheta
so
F-mgsinTheta-mg*mu*cosTheta= m*a
solve for F
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