Asked by Marina

How much force is needed to accelerate a 125 kg block up a 35 degree include at 3.4 m/s2 if the coefficient of friction is 0.28?

Answers

Answered by bobpursley
net force up= F-gravitydown-friction

= F-mgsinTheta-mg*mu*cosTheta

so

F-mgsinTheta-mg*mu*cosTheta= m*a
solve for F
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions