Asked by Anonymous
Jada throws a rock horizontally from a bridge 32 m above the water, which hits the water approximately 25 m from a point immediantly below the bridge. Show that Jade's tossing speed was about 10 m/s.
Answers
Answered by
Henry
h = Vo*t + 0.5g*t^2 = 32 m.
0 + 4.9t^2 = 32
t^2 = 6.53
Tf = 2.56 s. = Fall time.
Range = Xo * Tf = 25 m.
Xo * 2.56 = 25
Xo = 9.8 m/s. = Initial hor. velocity.
0 + 4.9t^2 = 32
t^2 = 6.53
Tf = 2.56 s. = Fall time.
Range = Xo * Tf = 25 m.
Xo * 2.56 = 25
Xo = 9.8 m/s. = Initial hor. velocity.
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