Asked by Vishal
A rock is thrown horizontally from a bridge with a velocity of 13.0 m/s. It takes the rock 3.5 s to strike the water below. What is the magnitude of the velocity of the rock just before it hits the water?
Answers
Answered by
bobpursley
vertical velocity=g*3.5
horizonal velocity=13
velocity=sqrt(13^2+(g*3.5)^2)
horizonal velocity=13
velocity=sqrt(13^2+(g*3.5)^2)
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