Asked by Jessica
A rock is thrown horizontally off of a cliff. It starts with a velocity of 4.2 m/s and the cliff is 68.2 m high.
How far out from the bottom of the cliff does the rock fall?
57m
59m
63m
45.8m
How far out from the bottom of the cliff does the rock fall?
57m
59m
63m
45.8m
Answers
Answered by
bobpursley
time to fall from height of clift:
68.2=1/2 g t^2
t= sqrt (68.2/4.9)=3.7 sec
distance horizontal= time*initial velocity
68.2=1/2 g t^2
t= sqrt (68.2/4.9)=3.7 sec
distance horizontal= time*initial velocity
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