Question
A boat is 23 mi due west of lighthouse A. Lighthouse B is 14 mi due north of lighthousenA. Find the bearing of lighthouse B from the boat and the distance from lighthousenB tho the boat.
Answers
X = -23 Mi.
Y = 14 Mi.
tanA = Y/X = 14/-23 = -0.60870
A = -31.33o,CW = 148.7o,CCW.
D = X/cosA = -23/cos148.7 = 26.9 Mi
Bearing = 148.7 - 90 = 58.7o.
Y = 14 Mi.
tanA = Y/X = 14/-23 = -0.60870
A = -31.33o,CW = 148.7o,CCW.
D = X/cosA = -23/cos148.7 = 26.9 Mi
Bearing = 148.7 - 90 = 58.7o.