Asked by Luke
A boat heads 15 degrees west of north with a water speed of 3 m/s. Determine its velocity relative to the ground when there is a 2 m/s current from 40 degrees east of north.
Answers
Answered by
Reiny
same type of question as your previous one.
Let's see you do some of the work, show me what you did.
Let's see you do some of the work, show me what you did.
Answered by
Writeacher
Kim = Luke!!
How silly to switch names. Pick one and keep it!
How silly to switch names. Pick one and keep it!
Answered by
Luke
I drew and labeled a triangle with one side to be found (v). I used the ‘z’ pattern to find 55 degrees. Then:
V^2= (2)^2+(3)^2-2(3)(2)cos 55
= 2.5 m/s
^this is correct, I just don’t really know how to find the angle (the text book answer is N56W but I got N41W using sine law
V^2= (2)^2+(3)^2-2(3)(2)cos 55
= 2.5 m/s
^this is correct, I just don’t really know how to find the angle (the text book answer is N56W but I got N41W using sine law
Answered by
Reiny
you were so close.
41.483° is indeed the angle within the triangle.
However, if you add 15° to that answer you get the direction of the boat.
N (41.483+15)° W or appr N 56 W.
btw, the question was to find its velocity <b>relative to the ground </b>
"relative to the ground" ? What does that even mean?
41.483° is indeed the angle within the triangle.
However, if you add 15° to that answer you get the direction of the boat.
N (41.483+15)° W or appr N 56 W.
btw, the question was to find its velocity <b>relative to the ground </b>
"relative to the ground" ? What does that even mean?
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