Asked by Anna
A motor boat heads west across a river as a current of 12 km/hr. The speedometer reads a constant of 26 km/hr. What is the resultant velocity of the boat as compared to its original path? And what is the degree?
Answers
Answered by
Henry
X = -26 km/h.
Y = -12 km/h(assuming a southbound current.
V^2 = X^2 + Y^2 = (-26)^2 + (-12)^2=820
Vb = 28.64 km/h.
tanAr = Y/X = -12/-26 = 0.46154
Ar = 24.8o. = Reference angle.
A = 180 + Ar = 180 + 24.8 = 204.8o,CCW.
= 24.8o South of West.
Y = -12 km/h(assuming a southbound current.
V^2 = X^2 + Y^2 = (-26)^2 + (-12)^2=820
Vb = 28.64 km/h.
tanAr = Y/X = -12/-26 = 0.46154
Ar = 24.8o. = Reference angle.
A = 180 + Ar = 180 + 24.8 = 204.8o,CCW.
= 24.8o South of West.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.