Asked by Jon
Write an equation in slope-intercept form for the line that passes through (3,5) and (-2,1).
y2-y1/x2-x1
1-5/-2-3
-4/-5= slope
y=mx+b
y=-4/-5(3)+b
-2=2.4+b
-4.4= y-intercept
y= -4/-5x+4.4 (answer)
y2-y1/x2-x1
1-5/-2-3
-4/-5= slope
y=mx+b
y=-4/-5(3)+b
-2=2.4+b
-4.4= y-intercept
y= -4/-5x+4.4 (answer)
Answers
Answered by
drwls
Rewrite the slope as m = 4/5. -4/-5 is the same thing but looks awkward.
y = (4/5) x + b
5 = [(4/5)*3] + b
5 = 12/5 + b
b = 13/5
y = (4/5)x + 13/5
y = (4/5) x + b
5 = [(4/5)*3] + b
5 = 12/5 + b
b = 13/5
y = (4/5)x + 13/5
Answered by
Jon
Ok, we lmow that the slope is 4/5.
y=mx+b
y=4/5(3)+b
-2=2.4+b
subtract 2.4 from both sides
-4.4 which is how I got the y-intercept
y= 4/5x+4.4
13/5 = 2.6 not 4.4
y=mx+b
y=4/5(3)+b
-2=2.4+b
subtract 2.4 from both sides
-4.4 which is how I got the y-intercept
y= 4/5x+4.4
13/5 = 2.6 not 4.4
Answered by
drwls
In solving for b, you took the x-value from one point (x=3) and, for y, you used the x value from the other point (x=-2) instead of y. You should have used y=5, as I did in my derivation. You have to use the x and y values of one known point to get the line to pass though that point.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.