Asked by Zach
                Batman (mass = 90 kg) jumps straight down from a bridge into a boat (mass = 530 kg) in which a criminal is fleeing. The velocity of the boat is initially +20 m/s. What is the velocity of the boat after Batman lands in it?
            
            
        Answers
                    Answered by
            drwls
            
    The total momentum for motion along the water does not change, assuming the water applies negligible retarding friction along that direction as the boat stabilizes. Therefore
M * 20 = (M + m)V
V = M*20/(M+m)
= (530/620)*20 m/s = ?
    
M * 20 = (M + m)V
V = M*20/(M+m)
= (530/620)*20 m/s = ?
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