Question
1) A man (mass = 80.9 kg) jumps straight down from a bridge into a boat (mass = 482 kg) in which a criminal is fleeing. The velocity of the boat is initially +14.5 m/s. What is the velocity of the boat after the man lands in it?
would I subtract the two masses and then multiply by the 14.5m/s?
would I subtract the two masses and then multiply by the 14.5m/s?
Answers
Elena
m2•v =(m1+m1) •u,
u=m2•v/(m1+m2) = 482•14.5/(482+80.9)= =12.42 m/s
u=m2•v/(m1+m2) = 482•14.5/(482+80.9)= =12.42 m/s