Asked by Emily
A bicycle has a speed of 7.5m/s at 4.3sec and a constant acceleration of 2.6m/s^2. the bicycle is at the origin (on the positive x-axis) when 1.2sec. How far from the origin is the bike at 7sec? Answer in units of m
Answers
Answered by
Elena
v=v₀ +a•t
v₀ = v-a•t = 7.5 -2.6•4.3 = -3.68 m/s.
x= x₀ + v₀•t +a•t²/2
x₀=x- v₀•t -a•t²/2 =0 – (-3.68•1.2) - 2.6•1.2²/2 = 4.416 - 0.052 = 4.364 m,
x= x₀ + v₀•t +a•t²/2 =
= 4.364 – 3.68•7 + 2.6•7²/2 =
= 4.364 – 25.76 + 63.7 = 42.304 m.
v₀ = v-a•t = 7.5 -2.6•4.3 = -3.68 m/s.
x= x₀ + v₀•t +a•t²/2
x₀=x- v₀•t -a•t²/2 =0 – (-3.68•1.2) - 2.6•1.2²/2 = 4.416 - 0.052 = 4.364 m,
x= x₀ + v₀•t +a•t²/2 =
= 4.364 – 3.68•7 + 2.6•7²/2 =
= 4.364 – 25.76 + 63.7 = 42.304 m.
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