Total area? each tire, or both? I am assuming both.
Weight=55*9.8N=areacontact*Pressure
pressure=55*9.8/.0022m^2
pressure will be in Pascals.
Weight=55*9.8N=areacontact*Pressure
pressure=55*9.8/.0022m^2
pressure will be in Pascals.
1. Calculate the force exerted by the cyclist and his bicycle:
The force exerted is given by the formula: force = mass x acceleration.
Assuming the acceleration is 0 (cyclist at rest), the force exerted is:
force = mass x acceleration = 55 kg x 0 = 0 N
2. Calculate the area of contact:
The total area of the tires in contact with the road is given as 2.2 x 10^-3 m^2.
3. Calculate the pressure exerted:
The pressure exerted is given by the formula: pressure = force / area.
Since the force is 0 N, the pressure exerted is:
pressure = 0 N / (2.2 x 10^-3 m^2) = 0 N/m^2
Therefore, the pressure exerted by the cyclist and his bicycle on the ground is 0 N/m^2, since the cyclist is at rest.
Pressure = Force / Area
First, we need to find the force exerted on the ground by the cyclist and the bicycle. The force can be calculated using Newton's second law of motion:
Force = Mass * Acceleration
Given that the combined mass of the cyclist and his bicycle is 55 kg, we know the mass.
Acceleration is not provided in the question, so we assume that the cyclist and his bicycle are at rest. In this case, the acceleration is zero since there is no change in velocity. Therefore, the force would be zero.
Next, we need to determine the area of the tires in contact with the road. The question states that it is 2.2 times (10 to the power of -3), but the value is not explicitly mentioned. Therefore, we need to calculate it.
Area = 2.2 * (10^-3)
Finally, we can calculate the pressure:
Pressure = Force / Area
Since the force is zero, the pressure would also be zero.