Asked by TUHITUHI

the middle digit of a no between 100 and 1000 is 0 the sum of the other digit is 11. if the digit be reversed the no so formed exeed the original no by 475 find the no..

Answers

Answered by Steve
the digits are htu
t=0
h+u=11
100h+10t+u + 475 = 100u + 10t + h
since t=0,
100h+u + 475 = 100u+h

h+u=11
99h - 99u + 475 = 0

902-209=693 no
803-308=495 no <---?
704-407=297 no
605-506=99 no

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